| Elements of Section - A3300 | ||
| Area of Section | 0.230 in2 (1.5 cm2) | |
Axis 1-1 | Axis 2-2 | |
| Moment of Inertia (I) | 0.017 in4 (0.7 cm4) | 0.052 in4 (2.2 cm4) |
| Section Modulus (S) | 0.038 in3 (0.6 cm3) | 0.083 in3 (1.4 cm3) |
| Radius of Gyration (r) | 0.269 in (0.7 cm ) | 0.477 in (1.2 cm ) |
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| Beam Loading - A3300 | ||||||
| Span (in) | Max Allowable Uniform | Defl at Uniform load (in) | Uniform Loading at Deflection | Lateral Bracing Reduction Factor | ||
| Span /180 (lbs) | Span /240 | Span /360 (lbs) | ||||
| 18 | 420 | 0.07 | 420 | 420 | 320 | 1.00 |
| 24 | 320 | 0.12 | 320 | 270 | 180 | 1.00 |
| 36 | 210 | 0.26 | 160 | 120 | 80 | 0.97 |
| 48 | 160 | 0.47 | 90 | 70 | 50 | 0.94 |
| 60 | 130 | 0.75 | 60 | 40 | 30 | 0.91 |
| 72 | 110 | 1.09 | 40 | 30 | 20 | 0.89 |
| 84 | 90 | 1.42 | 30 | 20 | 10 | 0.87 |
| 96 | 80 | 1.88 | 20 | 20 | 10 | 0.85 |
Notes:
- Above loads include the weight of the member. This weight must be deducted to arrive at the net allowable load the beam will support.
- Long span beams should be supported so as to prevent rotation and twist.
- Allowable uniformly distributed loads are listed for various simple spans, that is, a beam on two supports. If load is concentrated at the center of the span, multiply load from the table by 0.5 and corresponding deflection by 0.8.
- The lateral bracing factor should be multiplied by the load to determine the load retained based on the distance between lateral braces.
Bearing Load on Channel:
 |  |
| Max Load / 3,000 Lbs1,361 Kg | Max Load 2,000 Lbs907 Kg |
