Elements of Section - A3301 | ||
Area of Section | 0.459 in2 (3.0 cm2) | |
Axis 1-1 | Axis 2-2 | |
Moment of Inertia (I) | 0.077 in4 (3.2 cm4) | 0.104 in4 (4.3 cm4) |
Section Modulus (S) | 0.103 in3 (1.7 cm3) | 0.167 in3 (2.7 cm3) |
Radius of Gyration (r) | 0.411 in (1.0 cm ) | 0.477 in (1.2 cm ) |
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Beam Loading - A3301 | ||||||
Span (in) | Max Allowable Uniform | Defl at Uniform load (in) | Uniform Loading at Deflection | Lateral Bracing Reduction Factor | ||
Span /180 (lbs) | Span /240 | Span /360 (lbs) | ||||
18 | *990 | 0.03 | *990 | *990 | *990 | 1.00 |
24 | 860 | 0.07 | 860 | 860 | 850 | 1.00 |
36 | 580 | 0.15 | 580 | 560 | 380 | 1.00 |
48 | 430 | 0.27 | 420 | 320 | 210 | 0.99 |
60 | 350 | 0.43 | 270 | 200 | 140 | 0.95 |
72 | 290 | 0.62 | 190 | 140 | 90 | 0.91 |
84 | 250 | 0.85 | 140 | 100 | 70 | 0.88 |
96 | 220 | 1.11 | 110 | 80 | 50 | 0.84 |
*Load limited by weld shear |
Notes:
- Above loads include the weight of the member. This weight must be deducted to arrive at the net allowable load the beam will support.
- Long span beams should be supported so as to prevent rotation and twist.
- Allowable uniformly distributed loads are listed for various simple spans, that is, a beam on two supports. If load is concentrated at the center of the span, multiply load from the table by 0.5 and corresponding deflection by 0.8.
- The lateral bracing factor should be multiplied by the load to determine the load retained based on the distance between lateral braces.
Bearing Load on Channel:
Max Load 3,000 Lbs1,361 Kg | Max Load 2,000 Lbs907 Kg |